日期:23-03-13 時間:02:08 來源: 益榮金屬
求解方程組3-39可得:
A1=[W1+W2+(M0U+M0C)/N0]·cos[√(12N0/mL3)]T2-(mL3/12N0)(3R2v1/L2)·sin[√(12N0/mL3)]T2
A2=[W1+W2+(M0U+M0C)/N0]·sin[√(12N0/mL3)]T2+(mL3/12N0)(3R2v1/L2)·cos[√(12N0/mL3)]T2 (3-40)
將3-40式代入3-38式方程的通解為:
W(t)=[W1+W2+(M0U+M0C)/N0]·cos[√(12N0/mL3)]T2
-(mL3/12N0)(3R2v1/L2)·sin[√(12N0/mL3)]T2·cos[√(12N0/mL3)]t
+[W1+W2+(M0U+M0C)/N0]·sin[√(12N0/mL3)]T2
+(mL3/12N0)(3R2v1/L2)·cos[√(12N0/mL3)]T2·sin[√(12N0/mL3)]t-(M0U+M0C)/N0
整理上式:
W(t)=[W1+W2+(M0U+M0C)/N0]·sin[√(12N0/mL3)]T2 ·sin[√(12N0/mL3)]t
+cos[√(12N0/mL3)]T2·cos[√(12N0/mL3)]t
+(mL3/12N0)(3R2v1/L2)·cos[√(12N0/mL3)]T2·sin[√(12N0/mL3)]t
-sin[√(12N0/mL3)]T2 ·cos[√(12N0/mL3)]t-(M0U+M0C)/N0
=[W1+W2+(M0U+M0C)/N0]·cos[√(12N0/mL3)](t-T2)
+(mL3/12N0)(3R2v1/L2)·sin[√(12N0/mL3)](t-T2)-(M0U+M0C)/N0 (3-41)
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